28 February 2007
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the surprise that never was
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ANNOUNCEMENT: A teacher announces in the class that she will take a surprise quiz in the next week.
DEFINITIONS: 1) a: exactly one i.e. ((quiz on Xday)AND(quiz on Yday)) = FALSE [for all Xday and Yday] 2) surprise: it can never be determined with 100 % confidence on which day the quiz will be held i.e. (quiz on Xday) != TRUE [for any Xday] 3) in the next week: ((quiz on Monday)OR(quiz on Tuesday)OR(quiz on Wednesday)OR(quiz on Thursday)OR(quiz on Friday)) = TRUE
CLAIM 1: One of the student gets up and says that the surprise quiz cannot be on Friday, because
CLAIM 1.(i) If ((quiz on Monday)OR(quiz on Tuesday)OR(quiz on Wednesday)OR(quiz on Thursday)) = TRUE Then (quiz on Friday) = FALSE
PROOF 1.(i)
Case I: (quiz on Monday) = TRUE ==> ((quiz on Monday)AND(quiz on Friday)) = FALSE [exactly one quiz] but since (quiz on Monday) = TRUE hence, (quiz on Friday) = FALSE
Case II: (quiz on Tuesday) = TRUE ==> ((quiz on Tuesday)AND(quiz on Friday)) = FALSE [exactly one quiz] but since (quiz on Tuesday) = TRUE hence, (quiz on Friday) = FALSE
Case III: (quiz on Wednesday) = TRUE ==> ((quiz on Wednesday)AND(quiz on Friday)) = FALSE [exactly one quiz] but since (quiz on Wednesday) = TRUE hence, (quiz on Friday) = FALSE
Case IV: (quiz on Thursday) = TRUE ==> ((quiz on Thursday)AND(quiz on Friday)) = FALSE [exactly one quiz] but since (quiz on Thursday) = TRUE hence, (quiz on Friday) = FALSE
Case V: ((quiz on Monday = FALSE)AND(quiz on Tuesday = FALSE)AND(quiz on Wednesday = FALSE)AND(quiz on Thursday = FALSE)) = TRUE [for completeness of all the CASES] Let's take complement of both the sides, ==> ((quiz on Monday)OR(quiz on Tuesday)OR(quiz on Wednesday)OR(quiz on Thursday)) = FALSE But it contradicts with our assumption Hence, Case I to Case IV are complete representation of the given assumption. In Case I to Case IV, (quiz on Friday) = FALSE Hence, If ((quiz on Monday)OR(quiz on Tuesday)OR(quiz on Wednesday)OR(quiz on Thursday)) = TRUE Then (quiz on Friday) = FALSE
CLAIM 1.(ii) ((quiz on Monday)OR(quiz on Tuesday)OR(quiz on Wednesday)OR(quiz on Thursday)) = TRUE always
PROOF 1.(ii) Let's prove by contradiction. Let's assume that, ((quiz on Monday)OR(quiz on Tuesday)OR(quiz on Wednesday)OR(quiz on Thursday)) = FALSE But, ((quiz on Monday)OR(quiz on Tuesday)OR(quiz on Wednesday)OR(quiz on Thursday)OR(quiz on Friday)) = TRUE [as per the ANNOUNCEMENT] Hence, (quiz on Friday) = TRUE But, this contradicts with our definition of "surprise" Hence, this case is not possible
Combining both the claims, we get that (quiz on Friday) = FALSE always
Hence, we can update our definition of "in the next week"
DEFINITIONS(update): 3) in the next week: ((quiz on Monday)OR(quiz on Tuesday)OR(quiz on Wednesday)OR(quiz on Thursday)) = TRUE
CLAIM 2: Assuming CLAIM 1 to be true (and updated definitions), the quiz cannot be on Thursday
CLAIM 2.(i) If ((quiz on Monday)OR(quiz on Tuesday)OR(quiz on Wednesday)) = TRUE Then (quiz on Thursday) = FALSE
PROOF 2.(i) [Similar to PROOF 1.(i)]
CLAIM 2.(ii) ((quiz on Monday)OR(quiz on Tuesday)OR(quiz on Wednesday)) = TRUE always
PROOF 2.(ii) [Similar to PROOF 1.(ii)]
Combining both the claims, we get that (quiz on Thursday) = FALSE always
Continuing, we get (quiz on Wednesday) = FALSE, and (quiz on Tuesday) = FALSE
But, it was our initial assumption that (quiz on Monday)OR(quiz on Tuesday)OR(quiz on Wednesday)OR(quiz on Thursday)OR(quiz on Friday) = TRUE
Hence, (quiz on Monday) = TRUE But, this contradicts with our definition of "surprise" Hence, this case is not possible.
Hence, the ANNOUNCEMENT cannot be true.
Hence, no surprise quiz was held in the week :-)
Labels: comments, faith and temperance, intellectual, paradox, question, surprise quiz |
posted by Rohit Agarwal
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2 Comments: |
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try reading Hofstadter's Godel, Escher, Bach Seems like yr kinda book.
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the teacher was told this. she smiled and agreed.
on wednesday at 8 pm, she announced the test for wednesday.
the students were surprised!
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try reading
Hofstadter's Godel, Escher, Bach
Seems like yr kinda book.